deserialize
open override fun deserialize(json: JsonElement?, typeOfT: Type?, context: JsonDeserializationContext?): JSONResult<GeoJSONAttributes>?
Deserializes the JSON element based on the type property within the "geojson" node.
Return
The deserialized JSONResult<GeoJSONAttributes> object or null if the type is not supported.
Parameters
json
The JSON element to deserialize.
type
The expected type of the deserialized object (should be JSONResult<GeoJSONAttributes>).
context
The deserialization context from Gson.